3x^2+30x=33

Solution for 3x^2+30x=33 equation:

3x^2+30x=33

We move all terms to the left:

3x^2+30x-(33)=0

a = 3; b = 30; c = -33;
Δ = b2-4ac
Δ = 302-4·3·(-33)
Δ = 1296
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1296}=36$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(30)-36}{2*3}=\frac{-66}{6}
=-11
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(30)+36}{2*3}=\frac{6}{6}
=1
$